Question
What does the following code snipped print?
$a = 5;
$b = 'a';
print $$b;
Answer
This will print "5" because $$b tells PHP to use the value of the $b variable as a variable name, so as the value of $b is 'a' we are really looking at the value of $a; the $$b above could be replaced by $a and have the same output. This variable variable feature is a little obscure but it is useful to use in certain circumstances.
This can be taken a step further by using multiple levels of reference to access a variable by adding more dollar signs to the front of the variable name. All of the following will print out 5 because all of the print statements will point back to the variable $a.
$a = 5;
$b = 'a';
$c = 'b';
$d = 'c';
$e = 'd';
$f = 'e';
print $$b;
print $$$c;
print $$$$d;
print $$$$d;
print $$$$$e;
print $$$$$$f;Comments
It prints 5. That's because $$b is actually '$' + 'a' so the result is print $a