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PHP Question: Variable Reference
Question
What does the following code print out?
function arrayPrint($array)
{
echo implode(' ', $array);
}
$arrayA = [1, 2, 3];
$arrayB = $arrayA;
$arrayB[1] = 0;
arrayPrint($arrayA);
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Comments
arent they identical... apart from include() on fail produces a warning and the rest of the script can continue, whereas require() on fail will produce an error and the script will cease
Submitted by Ad on Wed, 04/13/2011 - 10:29
PermalinkThe difference between them is that require() will cause the script to fail if the file cannot be included, while include() will not.
Submitted by Brian Johnson on Wed, 04/13/2011 - 13:51
Permalinkinclude() produces a warning in the event the file is not available.
require() produces a fatal error in the event the file is not available.
Submitted by Anonymous on Thu, 04/14/2011 - 13:52
PermalinkI didn't know about this. I could have looked in the docs, but since you brought it up, I wanted to find out from you.
Submitted by Mihai Baboi on Fri, 04/15/2011 - 20:08
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